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Graham's Law Calculator

Chemistry

Compare how fast two gases effuse with Graham's law (r₁/r₂ = √(M₂/M₁)), identify an unknown gas from its rate or time, find where two gases meet in a diffusion tube, or count the stages needed to enrich uranium.

Quick Examples:

Calculator Settings

Input Values

Gas 1 effuses ___ times as fast as gas 2
For the speeds and the chart. It doesn't change the ratio.

Result

r₁ / r₂ = 3.984

H₂ effuses 3.984 times as fast as O₂.

In the same time, 3.984 times as many H₂ molecules find the pinhole. Lighter molecules move faster and hit the wall more often. Dots inside each box show how crowded the gas is; dots on the right have escaped through the pinhole.

r₁ / r₂
3.984
t₁ / t₂
0.251
M₂ / M₁
15.87
v̄ H₂
1770 m/s
v̄ O₂
444.2 m/s

Maxwell–Boltzmann Speed Distributions

% of molecules per 10 m/s

Molecular speed (m/s)

H₂
O₂

At the same temperature both gases have the same average kinetic energy, so the lighter one must move faster. The effusion rate follows the mean speed v̄ = √(8RT/πM).

Why it works
  • O₂ is 15.87 times heavier than H₂, but it effuses only √15.87 = 3.984 times slower: the rate goes with the square root of the mass.
  • At 25 °C both gases have the same average kinetic energy (3718 J/mol), so H₂ molecules average 1770 m/s and O₂ 444.2 m/s: the same 3.984 ratio.

Step-by-Step Solution

Graham's law: r₁ / r₂ = √(M₂ / M₁) (same temperature and pressure)

M₁ (H₂) = 2.016 g/mol, M₂ (O₂) = 32 g/mol

M₂ / M₁ = 32 / 2.016 = 15.87

r₁ / r₂ = √15.87 = 3.984

Assumptions
  • Ideal gases, effusing through a hole smaller than the distance a molecule travels between collisions.
  • Same temperature and pressure, unless the advanced panel is on.
  • Diffusion through another gas (the tube mode) follows the law only approximately.
  • For the speeds of a single gas, use the Ideal Gas Law Calculator (kinetic theory mode).

About This Tool

Graham's Law Calculator – Effusion Rates, Unknown Gases and the Ammonia Ring

Graham's law of effusion says that at the same temperature and pressure, a gas escapes through a pinhole at a rate inversely proportional to the square root of its molar mass. This Graham's law calculator compares two gases, identifies an unknown gas from its effusion rate or time, predicts where the white ring forms in the ammonia and hydrogen chloride tube, and counts the stages needed to enrich uranium by gaseous diffusion.

r₁ / r₂ = √(M₂ / M₁) t₁ / t₂ = √(M₁ / M₂) (same amount effused)

Effusion versus diffusion

The Scottish chemist Thomas Graham studied how gases spread out and escape in the 19th century. Two processes are easy to confuse. Effusion is gas leaking through a hole smaller than the distance a molecule travels between collisions, so molecules pass through one at a time. Diffusion is one gas spreading through another, with endless collisions along the way. Graham's law is exact for effusion and only approximate for diffusion, which is why the tube mode carries a caution.

Why the square root of the mass?

At the same temperature every gas has the same average kinetic energy, ½mv² = (3/2)kT. A heavier molecule must therefore move more slowly, and its speed scales as 1/√m. Faster molecules hit the wall, and so find the pinhole, more often. That is why oxygen, almost 16 times heavier than hydrogen, effuses only about 4 times more slowly. The speed-distribution chart in the calculator shows this directly, and the Ideal Gas Law Calculator works out the speeds of a single gas in its kinetic-theory mode.

Identifying an unknown gas

Squaring the law gives M₂ = M₁ × (r₁ / r₂)², or with times M₂ = M₁ × (t₂ / t₁)². If nitrogen takes 38.0 s to effuse and an unknown gas takes 64.5 s for the same amount, the unknown has a molar mass of about 80.7 g/mol, very close to hydrogen bromide. The calculator lists the nearest gases within 5 % so you can name the unknown.

The most common mistake
Rates and times are inverses. The lighter gas has the faster rate and the shorter time. If the answer comes out lighter than H₂, the ratio has been flipped.

The ammonia and hydrogen chloride tube

Cotton plugs soaked in ammonia and hydrochloric acid are pushed into opposite ends of a glass tube. Where the gases meet they react to form solid ammonium chloride, a white ring. Ammonia is the lighter gas, so it covers more of the tube and the ring forms nearer the HCl end, about 59 % of the way from the ammonia. In a real tube the gases diffuse through air, so the ring forms near the predicted point rather than exactly on it.

When the temperatures differ

The often-quoted rate ∝ √(T/M) quietly assumes both gases have the same number of molecules per litre. At equal pressure a hotter gas is less dense, and the molar effusion rate goes as 1/√(MT), so the hotter gas effuses more slowly in moles per second. The advanced panel makes you choose which quantity is held equal.

Uranium enrichment by gaseous diffusion

The Manhattan Project separated uranium isotopes by pushing uranium hexafluoride through porous barriers. Molecules of ²³⁵UF₆ and ²³⁸UF₆ differ in mass by less than 1 %, so an ideal stage enriches by a factor of only α ≈ 1.0043. Reaching reactor-grade uranium took hundreds to thousands of stages in series. Gas centrifuges, which need far fewer stages, later replaced diffusion plants.

Everyday effusion

A helium party balloon goes flat overnight while an air-filled one lasts for days: helium atoms are light and fast and leak through the rubber more easily. Sound also travels faster in light gases, which is why helium raises the pitch of your voice. The Speed of Sound Calculator works that out.

Frequently Asked Questions

Is the Graham's Law Calculator free?

Yes, Graham's Law Calculator is totally free :)

Can I use the Graham's Law Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Graham's Law Calculator?

Yes, any data related to Graham's Law Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

What is Graham's law of effusion?

Graham's law says that at the same temperature and pressure, the rate at which a gas escapes through a tiny hole is inversely proportional to the square root of its molar mass: r₁ / r₂ = √(M₂ / M₁). Hydrogen (2.016 g/mol) effuses about 3.98 times as fast as oxygen (32.00 g/mol), because 32.00 / 2.016 ≈ 15.9 and √15.9 ≈ 3.98.

What is the difference between effusion and diffusion?

Effusion is gas escaping through a hole smaller than the distance a molecule travels between collisions, so each molecule passes through on its own. Diffusion is one gas spreading through another, with constant collisions along the way. Graham's law is exact for effusion and only approximate for diffusion.

How do I find the molar mass of an unknown gas with Graham's law?

Measure its rate or effusion time against a known gas and square the ratio: M_unknown = M_known × (r_known / r_unknown)², or with times, M_unknown = M_known × (t_unknown / t_known)². The lighter gas always has the faster rate and the shorter time; if your answer is lighter than H₂, the ratio is probably upside down.

Why does the white ring form closer to the HCl end of the tube?

Ammonia (17.03 g/mol) is lighter than hydrogen chloride (36.46 g/mol), so it moves about √(36.46 / 17.03) ≈ 1.46 times as fast and covers more of the tube before the two meet. Graham's law predicts the meeting point about 59 % of the way from the ammonia end. Real rings land near that point rather than exactly on it, because the gases are diffusing through air.

Does temperature affect Graham's law?

Not when both gases share the same temperature: the ratio depends only on the molar masses. When the temperatures differ you must say what else is held equal. At equal concentration the rate follows the mean speed, √(T / M); at equal pressure the hotter gas has fewer molecules per litre and its molar rate goes as 1 / √(MT), so it effuses more slowly.

Why did uranium enrichment by diffusion need so many stages?

²³⁵UF₆ and ²³⁸UF₆ differ in mass by less than 1 %, so an ideal stage raises the isotope ratio by a factor of only √(352.04 / 349.03) ≈ 1.0043. Going from natural uranium (0.72 % ²³⁵U) to about 3 % takes 339 ideal stages, and real stages fall short of the ideal, which is why gaseous-diffusion plants needed hundreds to thousands of stages in series.