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Angular Momentum Calculator

Physics
Angular momentum is always measured about an axis
The same body has different angular momentum about different axes, so state the axis before quoting a number. Counter-clockwise in the viewing plane is taken as positive (+z) by the right-hand rule.

Worked examples

I = ½ m r²

Solid Disk / Solid Cylinder

ωI = ½ m r²

Angular momentum L

8.000

kg·m²/s

Counter-clockwise (+z)
kg·m²/sJ·sN·m·sg·cm²/slb·ft²/sslug·ft²/s
8.0008.0008.0008.000e+7189.8435.9007.586e+34
Moment of inertia I
0.400 kg·m²
Rotational KE
80.000 J
ω in RPM
190.986
ω in deg/s
1145.916
Rotation period T
0.314 s
Frequency f
3.183 Hz
Rim speed v = ω r
8.000 m/s
In units of ℏ
7.586e+34

L rises linearly with ω; energy rises quadratically

Torque needed to reach this L from rest

Required torque τ = ΔL / Δt
1.600 N·m

Step-by-step derivation

Shape: Solid Disk / Solid Cylinder

Mass (m) = 5 kg = 5.000000 kg

Radius (r) = 0.4 m = 0.400000 m

Formula: I = (1/2) × m × r²

I = 0.5 × 5.0000 × (0.4000)² = 0.400000 kg·m²

Angular velocity (ω) = 20 rad/s = 20.000000 rad/s

Formula: L = I × ω

L = 0.400 × 20.000 = 8.000 kg·m²/s

Cross-check: E = ½ I ω² = 80.000 J, and L²/(2I) = 80.000 J

Direction: Counter-clockwise (+z)

Display options

What the symbols mean

LIωθτα

Torque is the rate of change of angular momentum, τ = dL/dt, which is why the angular impulse mode and the Torque Calculator answer two halves of the same question.

About This Tool

Angular Momentum Calculator – Spin, Conservation and Torque

Angular momentum is the rotational counterpart of linear momentum: the quantity that a spinning body keeps hold of until something twists it. This angular momentum calculator handles both of the definitions you meet in a mechanics course — the point-particle form L = m·v·r·sin θ and the rigid-body form L = I·ω — and then follows them through to the problems they are actually used for: conservation, angular impulse, and the signed total for a system of several bodies.

Two formulas, one quantity

For a single mass moving past a chosen axis, angular momentum is the cross product L = r × p, whose magnitude is m·v·r·sin θ. Only the component of the motion perpendicular to the position vector counts, which is why the perpendicular lever arm r·sin θ appears. A 2 kg mass travelling at 15 m/s on the end of an 0.8 m string has p = 30 kg·m/s and L = 24 kg·m²/s. Tilt the velocity to 35° from the string and the same particle carries only 13.766 kg·m²/s.

For a rigid body turning about a fixed axis, every particle shares one angular velocity, and summing m·r² over the whole body gives the moment of inertia. Angular momentum then collapses to L = I·ω. A 5 kg solid disk of radius 0.4 m has I = ½mr² = 0.4 kg·m², so at 20 rad/s it carries L = 8 kg·m²/s and stores E = ½Iω² = 80 J of rotational energy.

Why the skater speeds up

The single most useful property of angular momentum is that it is conserved whenever the net external torque is zero, giving I₁ω₁ = I₂ω₂. A skater spinning at 2 rad/s with arms out at I₁ = 4.5 kg·m² carries L = 9 kg·m²/s. Pulling the arms in to I₂ = 1.5 kg·m² cannot change that number, so the spin rate triples to 6 rad/s.

Angular momentum is conserved; energy is not
In the same manoeuvre the rotational kinetic energy climbs from 9 J to 27 J. Because L is linear in ω while E is quadratic in it, thirding the inertia triples ω but triples the energy too. The extra 18 J is real muscular work done hauling the arms inward against the outward pull — it is not created by the conservation law.

Torque is the rate of change of angular momentum

Newton's second law for rotation is τ = dL/dt, which integrated over a constant torque gives the angular impulse ΔL = τ·Δt. Applying 12 N·m for 5 s to a 3 kg·m² rotor at rest delivers ΔL = 60 kg·m²/s, so ω_f = 60 / 3 = 20 rad/s. The same answer arrives through the angular acceleration route: α = τ/I = 4 rad/s² and ω = αΔt = 20 rad/s. The rotor sweeps θ = ½αΔt² = 50 rad, and the work τθ = 600 J matches ½Iω² = 600 J exactly — a cross-check the calculator prints on every run.

Units, signs and scale

The SI unit kg·m²/s is dimensionally identical to J·s and N·m·s, so those three columns always show the same number. Imperial engineering uses lb·ft²/s and slug·ft²/s, and quantum mechanics counts angular momentum in units of the reduced Planck constant ℏ = 1.0546 × 10⁻³⁴ J·s. Direction follows the right-hand rule: counter-clockwise in the viewing plane points out of the page and is taken as positive, clockwise as negative, which is what makes the multi-particle mode a signed sum rather than a plain total.

From flywheels to planets

The same arithmetic spans an enormous range. A reaction wheel on a satellite trades a few kg·m²/swith its spacecraft to point a camera. Earth's spin, modelled as a uniform sphere with I = ⅖mR² and ω = 2π/T, works out at roughly 7.07 × 10³³ kg·m²/s, while its orbit about the Sun carries about 2.66 × 10⁴⁰ kg·m²/s — some seven orders of magnitude more. Nothing in the formulas changes; only the exponents do, which is why the calculator switches to scientific notation automatically at those magnitudes.

Angular momentum is always about an axis
There is no such thing as the angular momentum of a body full stop — only its angular momentum about a stated point or axis. Move the axis and the number changes, so state the axis before quoting a value.

Frequently Asked Questions

Is the Angular Momentum Calculator free?

Yes, Angular Momentum Calculator is totally free :)

Can I use the Angular Momentum Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Angular Momentum Calculator?

Yes, any data related to Angular Momentum Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

How does the Angular Momentum Calculator work?

It converts every input to SI units first, then applies whichever of the two definitions matches your problem: L = m·v·r·sin θ for a point particle about an axis, or L = I·ω for a rigid body spinning about a fixed axis. Moments of inertia come from the same shape formulas the Moment of Inertia Calculator uses, so a 5 kg solid disk of radius 0.4 m gives I = ½mr² = 0.4 kg·m² and, at 20 rad/s, L = 8 kg·m²/s. Every mode shows the substitution line by line so you can check the arithmetic rather than trust it.

Why does pulling your arms in make a skater spin faster?

With no external torque acting, angular momentum is conserved, so I₁ω₁ = I₂ω₂. Dropping the moment of inertia from 4.5 to 1.5 kg·m² therefore triples the spin rate, from 2 rad/s to 6 rad/s. Kinetic energy is a different story: it rises from 9 J to 27 J, and that extra 18 J comes from the muscular work of hauling the arms inward against the outward pull.

Why is angular momentum conserved when kinetic energy is not?

They are conserved under different conditions. Angular momentum is conserved whenever the net external torque is zero, and internal forces cannot supply torque about the centre of mass. Kinetic energy is only conserved when no work is done, and internal forces absolutely can do work. Because L is linear in ω while E = ½Iω² is quadratic, halving I doubles ω but doubles the energy as well.

When should I use L = m·v·r·sin θ instead of L = I·ω?

Use the m·v·r form when a single mass moves past a chosen axis without being rigidly attached to it — a puck sliding by a post, a planet on its orbit, or a car rounding a bend measured about the centre of the curve. Use I·ω when the whole body rotates together about a fixed axis, such as a flywheel, a turbine rotor or a hard-disk platter. The two agree when the particle moves on a circle: substituting I = mr² and ω = v/r into I·ω returns m·v·r exactly.

What units does angular momentum use?

The SI unit is kg·m²/s, which is dimensionally identical to J·s and to N·m·s — all three are the same quantity written differently. Imperial work usually uses lb·ft²/s or slug·ft²/s, where 1 kg·m²/s equals 23.7304 lb·ft²/s or 0.73756 slug·ft²/s. Quantum mechanics measures angular momentum in units of the reduced Planck constant ℏ = 1.0546 × 10⁻³⁴ J·s, which is why the tool also reports the answer in ℏ.

How accurate are the celestial results?

The masses, radii and orbital data come from the NASA planetary fact sheets and are accurate to the digits shown, but the physical model is deliberately simple. Spin angular momentum assumes a uniform solid sphere with I = ⅖mR², which overstates I for real planets because their mass is concentrated toward the core — Earth's true value is closer to 0.33mR² than 0.4mR². Orbital angular momentum assumes a circular orbit, so it is a few parts per thousand off for eccentric orbits.