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Bernoulli Equation Calculator

Physics

The full three-term balance. Pick the quantity you do not know and the other five determine it.

One-click scenarios: the diver's hose, an aircraft pitot, a draining tank, a carburettor throat.

Fluid and units

m/s² — 9.80665 is standard gravity.

General balance

The named quantity is computed; every other field is an input. Balance check leaves them all as inputs.
In kPa.
In m/s.
In m, from any datum.
In kPa.
In m/s.
In m.

Result

P₂
166.8867 kPa
IncompressibleInviscidSteadyNo cavitation
What this model assumes
Bernoulli assumes steady, incompressible, inviscid, irrotational flow along a single streamline. It contains no friction term, so real pipe flow loses more pressure than shown here — these figures are an upper bound on downstream pressure and on flow rate.
Mach number
0.0175
166886.7000 Pa166.8867 kPa0.1669 MPa1.6689 bar1.6470 atm24.2049 psi1251.7566 mmHg49.2816 inHg

balance · total at 1 = 204500 Pa · total at 2 = 204500 Pa · residual 0.000e+0 Pa · closes ✓

cross-check · Back-substitution into the full three-term balance (total head at 1 vs at 2) = 204500 Pa · residual 0.000e+0 · agrees to double precision

cross-check · Head form: the same balance divided through by ρg, in metres of fluid = 20.853196555398632 m · residual 0.000e+0 · agrees to double precision

Energy breakdown

TermPoint 1Point 2
Static pressure P (kPa)200.0000166.8867
Dynamic ½ρv² (kPa)4.500018.0000
Hydrostatic ρgh (kPa)0.000019.6133
Total (kPa)204.5000204.5000
Stagnation P + ½ρv² (kPa)204.5000184.8867
Velocity (m/s)3.00006.0000
Pressure head (m)20.394317.0177
Velocity head (m)0.45891.8355
Total head (m)20.853220.8532

Diagram

Two stacked bars of equal total height, one per point, split into static pressure, dynamic pressure and the elevation term. The totals match because Bernoulli is a conservation statement.Point 1Point 2static · dynamic · elevationdashed line = the shared total

Model validity

IncompressibleM = 0.0174927113703 against air's 343 m/s. Liquids are effectively incompressible regardless.

InviscidNo friction term. Real pipe flow loses more pressure than shown, so downstream pressure and flow rate here are upper bounds.

SteadySteady flow assumed: nothing in the balance varies with time.

No cavitationLowest absolute pressure 268211.7 Pa is above the ~2339 Pa vapour pressure of water at 20 °C.

1. ρ = 1000 kg/m³, g = 9.80665 m/s²

2. Point 1: P = 200000 Pa gauge, v = 3 m/s, h = 0 m

3. Point 2: P = 166886.7 Pa gauge, v = 6 m/s, h = 2 m

4. ½ρv₁² = 4500 Pa · ½ρv₂² = 18000 Pa

5. ρgh₁ = 0 Pa · ρgh₂ = 19613.3 Pa

6. Total at 1 = 204500 Pa · Total at 2 = 204500 Pa

7. Solved P₂ = 166886.7 Pa

Worth knowing
Acceleration accounts for -13500 Pa of the pressure change and the elevation change for -19613.3 Pa.

About This Tool

Bernoulli Equation Calculator – Venturi Meters, Pitot Tubes, Torricelli Efflux and the Pressure–Velocity Trade-off

Squeeze a garden hose and the jet shoots further. Blow across the top of a sheet of paper and it lifts. Both are the same statement: in a moving fluid, where the speed goes up the pressure comes down. This Bernoulli equation calculator puts numbers on that trade-off, solving the steady-flow energy balance for whichever quantity you do not know and coupling it to continuity so a change of pipe diameter alone is enough to fix both velocities.

The equation, and what each term is

Along a single streamline in a steady, incompressible, frictionless flow, three quantities trade against one another but always sum to the same total:

P₁ + ½ρv₁² + ρgh₁ = P₂ + ½ρv₂² + ρgh₂

P is the static pressure— what a flush tap in the pipe wall reads. ½ρv² is the dynamic pressure, the kinetic term, which only shows up when you bring the flow to rest. ρgh is the hydrostatic term for height above your chosen datum. Their sum is the total pressure, and it is the invariant the whole tool rests on. Add the three terms at each point and the two totals must match; the results panel prints them side by side with the residual, so the conservation is something you can check rather than something you are told.

Take water at 200 kPa gauge moving at 3 m/s, accelerating to 6 m/s while climbing 2 m. The speed-up costs 13.5 kPa and the climb costs 19.6133 kPa, leaving 166.8867 kPa downstream. Both totals come to 204500 Pa exactly.

Continuity: why a narrower pipe means faster flow

Mass cannot pile up in a rigid pipe, so A₁v₁ = A₂v₂ = Q. Halve the bore and the area falls by four, so the speed quadruples. Run 10 L/s through an 80 mm pipe narrowing to 40 mm and the flow goes from 1.9894 m/s to 7.9577 m/s, costing 29.6839 kPa of static pressure. That is the whole mechanism behind a Venturi meter: measure the pressure drop across a known constriction and you have the flow rate without putting anything in the stream.

The four classic applications

A Venturi meter inverts the balance to give velocity from a measured drop: v₁ = √(2ΔP / (ρ((A₁/A₂)² − 1))). A Pitot tube uses the two-term form along a stagnation streamline, so v = √(2(P₀ − P)/ρ) — in sea-level air, 850 Pa of dynamic pressure is 37.25 m/s, or 134.1 km/h. Torricelli efflux is the tank case, where both ends sit at atmospheric and the pressure terms cancel to leave v = √(2gh); three metres of head gives 7.6707 m/s. And the general solve handles any single unknown among the eight state quantities.

Static, dynamic and stagnation pressure

These three get confused constantly. Static pressure is what the fluid exerts sideways on the pipe wall. Stagnation (or total) pressure is P + ½ρv²— what a probe facing into the flow reads, because it stops the fluid and converts all the kinetic energy back into pressure. The difference between them is the dynamic pressure, and that difference is precisely what an airspeed indicator measures. Every result here breaks the total into its three parts for both points, so which term paid for which is never a guess.

Where Bernoulli stops being true

There is no friction term
Bernoulli assumes steady, incompressible, inviscid, irrotational flow along a single streamline. Real pipe flow always loses more pressure than this predicts, so every downstream pressure and every flow rate here is an upper bound. For a long pipe run use Darcy–Weisbach or Hazen–Williams instead.

Four other regimes break it. Above roughly Mach 0.3 the constant-density assumption fails, which is why the tool reports a Mach number rather than leaving you to check. Downstream of a sudden expansion the flow separates and there is no single well-defined streamline, so a diffuser raises a warning. Unsteady flow— a tank that is visibly draining — is quasi-steady at best. And any pump, turbine or heater between the two points adds or removes energy and puts the problem outside Bernoulli entirely.

Discharge coefficients are not fudge factors

A sharp-edged orifice passes far less than the ideal figure — typically about 62 %, so 3.7654 L/s becomes 2.3345 L/s. That gap is the vena contracta and viscous loss, both real physics the frictionless model omits, and the tool labels it as a model correction rather than filing it with the rounding noise. The residuals it reports for its own second routes are of order 10⁻¹² Pa; a 38 % discharge correction is a different kind of thing entirely, and the two should never be read in the same register.

Negative gauge pressure is a feature

Push 8 L/s through a 100 mm pipe necking to 40 mm and the throat lands at −4745.47 Pa gauge. That is not an error — it is suction, and it is exactly how a carburettor lifts fuel and an eductor pulls water. The tool reports the absolute pressure alongside, checks it against the fluid's vapour pressure, and warns only when the liquid would actually cavitate.

Frequently Asked Questions

Is the Bernoulli Equation Calculator free?

Yes, Bernoulli Equation Calculator is totally free :)

Can I use the Bernoulli Equation Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Bernoulli Equation Calculator?

Yes, any data related to Bernoulli Equation Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

How does this Bernoulli equation calculator work?

It solves P₁ + ½ρv₁² + ρgh₁ = P₂ + ½ρv₂² + ρgh₂ for whichever quantity you leave to it, and couples that balance to continuity (A₁v₁ = A₂v₂) so a pipe diameter change alone determines both velocities. Everything is computed in SI at full double precision and rounded only for display, and every mode is closed by a second, independent route whose residual is shown.

Why does pressure drop where the pipe gets narrower?

Continuity forces the fluid to speed up through a constriction, and the energy for that acceleration has to come from somewhere. It comes out of the static pressure term, so the throat reads lower. Nothing is lost — the total of static, dynamic and elevation pressure is the same at both points, which the balance-check row makes visible.

What is the difference between static, dynamic and stagnation pressure?

Static pressure P is what a flush wall tap reads. Dynamic pressure ½ρv² is the kinetic term, which only appears when the flow is brought to rest. Stagnation (total) pressure P + ½ρv² is what a forward-facing probe reads. A Pitot tube measures the difference between the last two, and that difference is exactly the dynamic pressure.

Why is my real flow rate lower than this calculator predicts?

Bernoulli has no friction term, so every figure it produces is an upper bound. Real pipes lose pressure to viscosity and fittings, and real orifices contract the jet — which is why a sharp-edged orifice typically passes only about 62 % of the ideal flow. Enter a discharge coefficient to see the corrected figure, and use Darcy–Weisbach rather than Bernoulli for a long pipe run.

Can the throat pressure really be negative?

A negative gauge pressure just means below atmospheric, which is entirely physical and is how a Venturi draws fuel into a carburettor or water into an eductor. The calculator reports it with the absolute pressure alongside. What it will not accept is a negative absolute pressure, and it warns when the absolute pressure falls below the fluid's vapour pressure, because the liquid would cavitate there.

When does the Bernoulli equation stop being valid?

It assumes steady, incompressible, inviscid, irrotational flow along a single streamline. It breaks down in long or viscous pipes where friction dominates, above roughly Mach 0.3 where density stops being constant, downstream of a sudden expansion where the flow separates, in genuinely unsteady flow, and across any pump, turbine or heater that adds or removes energy. The results panel evaluates each of those against your numbers rather than just listing them.