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Hydrostatic Pressure Calculator

Physics

P = ρ·g·h at a single depth, gauge and absolute — or run it backwards to recover the depth or the fluid density.

One-click scenarios from the physics literature.
Real depths, from the shallow end to the Challenger Deep.

Fluid and environment

m/s² — 9.80665 is standard gravity.
In Pa. Zero means a vacuum above the fluid.

Pressure at depth

In m.

Result

Gauge pressure
100518.1625 Pa
Gauge
100518.1625 Pa
Absolute
201843.1625 Pa
Specific weight γ
10051.8162 N/m³
100518.1625 Pa100.5182 kPa0.1005 MPa1.0052 bar0.9920 atm14.5789 psi753.9503 mmHg29.6830 inHg1.0250 kgf/cm²

cross-check · Weight of the fluid column on a 0.37 m² test area ÷ that area = 100518.1625 Pa · residual 0.000e+0 Pa · agrees to double precision

Diagram

A tank shaded from light at the free surface to dark at the bottom, with a marker at 10.00 metres where the gauge pressure is 100518.16 pascals.free surface · P₀ = 101325.0000 Pa10.00 m · 100518.1625 Pa

Equivalent head

Fresh water
10.2500 m
Seawater
10.0000 m
Mercury (0 °C)
0.7539 m

1. ρ = 1025 kg/m³, g = 9.80665 m/s², h = 10 m

2. P_gauge = 1025 × 9.80665 × 10 = 100518.1625 Pa

3. P_abs = 100518.1625 + 101325 = 201843.1625 Pa

4. γ = ρ · g = 10051.81625 N/m³ (pressure gained per metre of depth)

About This Tool

Hydrostatic Pressure Calculator – Depth, Dam Thrust, Manometers and the Hydrostatic Paradox

Dive to ten metres and your ears know it instantly. Stand at the foot of a dam and the wall is thick for a reason. Both come from one short equation: a fluid at rest presses on everything below its surface with a hydrostatic pressure that grows in direct proportion to depth. This hydrostatic pressure calculatorworks in every direction around that relation — pressure at a depth, the force on a submerged wall and where it acts, manometer readings, hydraulic presses, atmospheric pressure at altitude, stacked fluid layers, and the container-shape paradox that trips up almost everyone.

The one equation everything comes from

Gauge pressure is density times gravity times depth, and absolute pressure adds whatever sits on the free surface:

P_gauge = ρ · g · h and P_absolute = P_gauge + P₀

A diver at 10 m in seawater (ρ = 1025 kg/m³) feels 1025 × 9.80665 × 10 = 100518.1625 Pa of gauge pressure, or 201843.1625 Paabsolute — almost exactly double the pressure at the surface. The quantity ρg is the specific weight, the slope of the pressure-versus-depth line: seawater gains 10051.81625 Pa per metre, fresh water 9806.65 Pa. Because the relation is linear, the whole profile is a straight line through the origin, and rearranging it solves for depth (h = P/ρg) or fluid density (ρ = P/gh) just as easily.

The hydrostatic paradox: shape does not matter

Look at what is missing from P = ρgh. There is no term for volume, no term for width, no term for the shape of the vessel. Fill a straight cylinder, a cone that narrows upward and a funnel that flares upward all to a depth of 0.8 m of water and every one of them reads 7845.32 Pa at the base. On a 0.02 m² base that is 156.9064 Nof downward force in each — even though the funnel holds seven times as much water as the cone.

Why the paradox is not a contradiction
The cone contains only 52.30 N of water yet its base feels 156.91 N. The extra 104.60 N comes from the sloping walls, which push down on the fluid trapped beneath them. In the flaring funnel the accounting reverses: the walls carry part of the weight upward, so the base feels 209.21 N less than the water weighs. Only in a straight-walled cylinder do base force and fluid weight agree exactly.

Force on a dam, and where it acts

Total thrust on a submerged plane surface is the pressure at its centroid times its area, F = ρ · g · ȳ · A. A dam face 6 m deep and 4 m wide takes 706078.8 N. The resultant does not act at mid-depth, though: because the lower strips are pushed harder, it acts at the centre of pressure, y_cp = ȳ + I_c/(ȳ · A), which for a surface-piercing wall simplifies to exactly 2H/3 — here 4 m down, one third of the way up from the base. That is why dams are built thickest at the bottom. Sink the same panel deeper and the offset shrinks: a 2 m gate whose top edge is 3 m down has its centre of pressure just 8.3 cm below its centroid.

Manometers, presses and altitude

A U-tube manometer turns a column height into a pressure: P = ρ_gauge · g · Δh, so 250 mm of mercury reads 33180.8 Pa. In a differential manometer you must subtract the displaced process fluid, ΔP = (ρ_gauge − ρ_process) · g · Δh— the step most often forgotten. A hydraulic pressis Pascal’s principle at work: a 50 mm piston driving a 300 mm piston multiplies force by 36, but the big piston moves only one thirty-sixth as far, so work in equals work out. Going the other way, the barometric formula P = P₀·(1 − Lz/T₀)^5.2558 gives 31444.6 Paon the summit of Everest — under a third of sea-level pressure.

Layers, vacuum and the limits of the model

With immiscible fluids stacked in a tank the contributions simply add, P = g · Σ(ρᵢ · hᵢ), and the pressure profile kinks at each interface because every layer has its own slope. Gauge pressure is also allowed to go negative: a suction pipe lifting water 7 m sits at −68646.55 Pa gauge, and no pump anywhere can lift fresh water past 10.3322745 m, because that is all the head one atmosphere can support.

Where the numbers stop being exact
The fluid is modelled as incompressible and uniform, so deep-ocean figures are underestimates — real seawater compresses several percent near the bottom of the Mariana Trench. The fluid must also be at rest; flowing pipes and accelerating tanks need different equations. And a “mmHg” scale is defined on mercury at 0 °C (13595.1 kg/m³), not the 13534 kg/m³of room-temperature mercury — a real 0.451 % difference the calculator flags rather than hides.

Every mode recomputes its answer by a second, independent route and prints the residual between the two, so the result arrives already checked. Enter your own fluid, depth, gravity and surface pressure to see the full derivation at each step.

Frequently Asked Questions

Is the Hydrostatic Pressure Calculator free?

Yes, Hydrostatic Pressure Calculator is totally free :)

Can I use the Hydrostatic Pressure Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Hydrostatic Pressure Calculator?

Yes, any data related to Hydrostatic Pressure Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

How does this hydrostatic pressure calculator work?

Everything starts from P = ρ·g·h — the pressure a still fluid exerts at a depth h below its free surface — with the absolute pressure obtained by adding whatever pressure sits on that surface, normally one atmosphere. Pick the question you are actually asking: pressure at a depth, a pressure-versus-depth profile, the thrust and centre of pressure on a dam or gate, a U-tube or differential manometer, a hydraulic press, atmospheric pressure at altitude, a stack of immiscible layers, or the hydrostatic paradox. Every input is converted to SI, the whole calculation runs in SI, and rounding happens only when the numbers are printed. Each mode also recomputes its answer by a second, independent route and reports the residual, so you can watch the arithmetic check itself instead of trusting a single number.

Why does the shape of the container not change the pressure at the bottom?

Because P = ρ·g·h has no term for volume, width or shape — only the vertical distance down to the free surface appears in it. Fill a straight cylinder, an upward-narrowing cone and a flaring funnel to the same depth of 0.8 m with water and all three read exactly 7845.32 Pa at the base, even though the funnel holds seven times as much water as the cone. Multiply by a 0.02 m² base and every one of them pushes down with 156.9064 N. The cone only contains 52.30 N of water, so its base feels 104.60 N more than the fluid above it weighs; the sloping walls supply that difference by pushing down on the fluid. That mismatch between base force and fluid weight is the resolution of the paradox, not an error.

Where does the total force on a dam wall actually act?

Not at mid-depth. The resultant acts at the centre of pressure, y_cp = ȳ + I_c/(ȳ·A), which always sits below the centroid because pressure grows with depth and the deeper strip of wall is pushed harder. For a wall reaching the free surface the formula collapses to the neat closed form y_cp = 2H/3, exactly H/6 below the centroid: a 6 m dam face 4 m wide carries 706078.8 N acting 4 m down, one third of the way up from the base. As a gate is sunk deeper the offset shrinks — a 2 m gate whose top edge is 3 m down has its centre of pressure only 8.3 cm below its centroid — because the pressure gradient becomes small next to the mean pressure.

Is 10 metres of water really one atmosphere?

Close, but not exact, and the tool quantifies the gap rather than repeating the rule of thumb. Ten metres of fresh water gives 1000 × 9.80665 × 10 = 98066.5 Pa, which is 0.9678 atm — about 3.2 % short. One full atmosphere of gauge pressure needs 10.3322745 m of fresh water, or 10.0803 m of seawater at 1025 kg/m³. That same number is why no suction pump can lift water more than about 10.33 m: a perfect vacuum above the column can only be balanced by 1 atm of head, and in practice the water boils (cavitates) before that, once the absolute pressure falls below its vapour pressure of roughly 2.3 kPa at 20 °C.

Why does a mercury manometer disagree with an mmHg reading?

Because the two use different mercury. The millimetre-of-mercury unit is defined on mercury at 0 °C, 13595.1 kg/m³, while the mercury sitting in a laboratory manometer is at room temperature and closer to 13534 kg/m³. A 250 mm column computes to 33180.8003 Pa from ρgh at 13534, but an instrument with an mmHg scale reports 33330.5969 Pa — a real 0.451 % disagreement, not rounding noise. The calculator keeps the two densities strictly separate, offers 0 °C mercury as its own preset, and labels which density produced any mmHg figure, so the two paths are never silently mixed.

How accurate are the results, and what do they assume?

The arithmetic is exact to double precision and every mode is cross-checked by an independent second route, but the physics carries assumptions worth knowing. The fluid is treated as incompressible and of uniform density, so deep-ocean figures are underestimates — real seawater compresses several percent near 11 km, which the tool warns about. The fluid is assumed to be at rest, so nothing here covers flowing pipes, waves or accelerating tanks. Gravity is constant over the depth involved, and the barometric mode uses the standard-atmosphere lapse rate, which stops being valid above the tropopause at about 11 km. Gauge pressure is deliberately allowed to go negative, because suction and vacuum are perfectly physical.