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Orbital Velocity Calculator

Physics
Ideal two-body orbits, scientific notation welcome
Every numeric field accepts values like 5.972e24 or 4.2164e7. Results assume a point-mass central body with no oblateness, third-body, drag or radiation-pressure perturbations, so real mission numbers differ slightly.

Worked examples

Central body and orbit

Elliptical orbits use the vis-viva equation.
Pick the unknown; supply the rest.
Currently: Earth
Altitude is measured above the surface radius below.
The mass being orbited — Earth is 5.972e24 kg.
Used to convert altitudes and to reject orbits inside the body.
Height above the surface — 400 km is the ISS.
Adds the orbital energy and momentum panel. Leave blank to hide it.
Adds the two-burn transfer budget, in km. Leave blank to hide it.

Orbit around Earth

Circularsub-synchronous
Orbital velocity (v)
7.672 km/s

7,672.49 m/s · 27,621 km/h · 17,163 mph

Orbital period (T)
5,544.933 s

1.54 hours · 15.58 orbits per day

Escape velocity at this radius
10.851 km/s

Burn 3.178 km/s more to leave orbit entirely.

Orbital radius (r)

6,771 km

Altitude (h)

400 km

Central mass (M)

5.972 × 10^24 kg

Gravitational parameter (µ)

3.986 × 10^14 m³/s²

Derived orbital properties

Angular velocity (ω = v/r)

1.133 × 10^-3 rad/s

Specific angular momentum (h)

5.195 × 10^10 m²/s

Specific orbital energy (ε)

-29.434 MJ/kg

Centripetal acceleration

8.694 m/s²

Semi-major axis (a)

6,771 km

Fraction of light speed

2.559 × 10^-5 c

µ = G·M

µ = 6.6743e-11 × 5.9720e+24

µ = 3.9859e+14 m³/s²

r = R + h

r = 6.3710e+6 + 4.0000e+5

r = 6.7710e+6 m

v_o = √(µ / r)

v_o = √(3.9859e+14 / 6.7710e+6)

v_o = 7672.49 m/s

T = 2πr / v_o

T = (2π × 6.7710e+6) / 7672.49

T = 5544.9 s

v_e = √2 · v_o

v_e = 1.41421 × 7672.49

v_e = 10850.54 m/s

G = 6.674 × 10^-11 m³/(kg·s²) · one sidereal day = 86,164.09 s

Well-known Earth orbits

Pick up to eight orbits. Every row is computed independently around Earth (M = 5.972e24 kg, R = 6,371 km), which makes the inverse relationship between altitude and speed obvious.

OrbitAltitude (km)Radius (km)Velocity (km/s)PeriodEscape v (km/s)Orbits/day
Low Earth orbit (300 km)3006,6717.731.51 hours10.93215.93
ISS (400 km)4006,7717.6721.54 hours10.85115.58
Sun-synchronous (700 km)7007,0717.5081.64 hours10.61814.6
GPS / MEO (20,200 km)20,20026,5713.87311.97 hours5.4772
Geostationary (35,786 km)35,78642,1573.07523.93 hours4.3491
Moon (384,400 km)378,029384,4001.01827.45 days1.440.04

About This Tool

Orbital Velocity Calculator – Speed, Period and Delta-v

The Orbital Velocity Calculator works out how fast a satellite, moon or planet has to travel to stay in orbit around a central body. Choose a planet, moon or star from the presets — or enter your own mass and radius — give an altitude, a radius or a target period, and the tool returns the orbital velocity, the orbital period, the escape velocity at the same radius and the delta-v that separates the two.

Where the Formula Comes From

An orbit is a permanent free fall: gravity supplies exactly the centripetal acceleration the curved path demands. Setting GMm/r² = mv²/r and cancelling the satellite mass m leaves the circular relation:

v_o = √(GM / r)          circular orbital speed
T   = 2πr / v_o          orbital period
v_e = √2 · v_o           escape speed at the same radius

G  gravitational constant, 6.6743 × 10⁻¹¹ m³/(kg·s²)
M  mass of the central body (kg)
r  distance from the central body's centre (m)

Two consequences follow at once. Orbital speed does not depend on the satellite's mass — a loose bolt and a 420-tonne space station at 400 km altitude both travel at about 7.67 km/s and lap the planet every 92 minutes. And because speed falls off as 1/√r, higher orbits are slower: geostationary satellites at 35,786 km drift along at just 3.07 km/s.

Elliptical Orbits and the Vis-Viva Equation

Real orbits are usually ellipses, and the general speed law is the vis-viva equation v = √(GM(2/r − 1/a)), where a is the semi-major axis. The circular case is simply a = r, so the calculator implements the elliptical form once and lets circular orbits call it. A geostationary transfer orbit with a 200 km periapsis and a 35,786 km apoapsis has a = 24,368 km and eccentricity e = 0.73: it races through periapsis at 10.24 km/s and crawls through apoapsis at 1.60 km/s. The ratio of those speeds equals the inverse ratio of the radii, which is Kepler's second law expressed as conservation of angular momentum.

Solving Backwards: Radius, Period and Planet Masses

Kepler's third law, T = 2π√(a³/GM), inverts in two useful directions. Fix the period and you get the radius that produces it — feed in one sidereal day, 86,164 s, and the tool returns the geostationary radius of 42,164 km. Fix the radius and period of an observed satellite and you get the central mass from M = 4π²r³/(GT²). Measuring the Moon at 384,400 km with a 27.32-day period recovers Earth's mass to within about 1%, which is how astronomers weigh planets, stars and black holes they will never visit.

Delta-v, Transfers and Orbital Energy

Because v_e = √2 · v_o, a craft already in a circular orbit needs only 41.4% more speed to escape — about 3.18 km/s from low Earth orbit. Moving between two circular orbits is cheapest with a Hohmann transfer: one burn raises apoapsis onto an ellipse touching the target, a second burn circularises there. From a 200 km parking orbit to geostationary that costs roughly 2.46 km/s plus 1.48 km/s, about 3.93 km/s in total, over a 5.3-hour coast. Supply a satellite mass and the calculator also reports kinetic, potential and total orbital energy E = −GMm/2a, which stays negative for every bound orbit and rises toward zero as the orbit climbs.

Limits of the Model

Results assume an ideal two-body problem with a spherical, point-mass central body. Real orbits are perturbed by planetary oblateness, third bodies, solar radiation pressure and — below roughly 200 km — by atmospheric drag strong enough to decay an unpowered orbit within days. Treat the figures as accurate to three or four significant digits and as the starting point that mission analysts refine numerically.

Frequently Asked Questions

Is the Orbital Velocity Calculator free?

Yes, Orbital Velocity Calculator is totally free :)

Can I use the Orbital Velocity Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Orbital Velocity Calculator?

Yes, any data related to Orbital Velocity Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

How does the Orbital Velocity Calculator work?

It equates gravitational attraction with the centripetal force a curved path needs, GMm/r² = mv²/r, which reduces to v = √(GM/r) for a circular orbit. Pick a central body preset or type your own mass, give an altitude or radius, and the tool returns the orbital speed together with the period, the escape velocity at the same radius and a step-by-step derivation. Elliptical orbits use the vis-viva form v = √(GM(2/r − 1/a)).

Why doesn't orbital velocity depend on the satellite's mass?

The satellite's mass m appears on both sides of GMm/r² = mv²/r and cancels completely. A bolt and a space station at the same altitude therefore travel at exactly the same speed. Only the energy and momentum needed to put the object there scale with its mass, which is why those are reported in a separate panel.

Why are higher orbits slower but harder to reach?

Speed falls off as 1/√r, so a satellite at geostationary altitude moves at 3.07 km/s while the ISS at 400 km moves at 7.67 km/s. Total orbital energy, −GMm/2a, still rises toward zero as the orbit gets higher, so the higher orbit holds more energy overall. The extra potential energy gained outweighs the kinetic energy given up.

What is the difference between orbital and escape velocity?

At any radius the escape velocity is exactly √2 times the circular orbital velocity, about 41.4% faster. A spacecraft already circling at 400 km needs only about 3.18 km/s more to leave Earth entirely rather than the full 11.2 km/s from the ground, which is why the calculator prints both figures side by side.

How is the geostationary altitude calculated?

Set the orbital period equal to one sidereal day, 86,164 s, and invert Kepler's third law: a = (GM·T²/4π²)^(1/3) gives about 42,164 km from Earth's centre, or 35,786 km of altitude, where the orbital speed is roughly 3.07 km/s. Choose the period-constrained mode to reproduce that derivation for any body and any target period.

How accurate are the results for real missions?

The model is an ideal two-body problem with a point-mass central body, so figures match published values to three or four significant digits. Real orbits are perturbed by the oblateness of the planet (the J2 term), third bodies, solar radiation pressure and atmospheric drag, so mission planners refine these numbers with numerical propagation. Below roughly 200 km altitude drag matters enough that an unpowered orbit decays within days.